try—catch can‘t catch the exception，cause when exception happend，enter recursion in catch ，try block dont work and just into the catch block

Question

package object.myobject;

import java.util.Scanner;

public class CatchTheException {
    Scanner scanner = new Scanner(System.in);

    void receiveInt(){
        System.out.println("please input an int");
        try{
            System.out.println(scanner.nextInt());
            System.out.println("try block wont work");
        }catch (Exception e){
            System.out.println(e);
            System.out.println("the input is wrong, please input again");
            receiveInt();
        }
    }

    public static void main(String[] args) {
        new CatchTheException().receiveInt();

    }
}

I don't know why the try block wont work，maybe is the exception not catched？ I’m a newbie of the try catch. i run and try block wont work make the recursion wont stop, so i get a stackoverflow exception

Answer 1

Here An Alternative way to do this sort of thing:

Scanner scanner = new Scanner(System.in);
String num = "";
while (num.isEmpty()) {
    System.out.print("Please enter an integer value: -> ");
    num = scanner.nextLine().trim();
    /* Is the supplied value a string representation of a
       signed or unsigned integer value?     */
    if (!num.matches("-?\\d+")) {
        System.out.println("Invalid Entry (" + num + ")! Try again...\n");
        num = ""; // Ensure re-loop
    }
}
        
// Passed entry validation:
int number = Integer.parseInt(num);  // Convert string value to Integer type:
System.out.println("Your Number: -> " + number);