I don't want to call the parent constructor. Can we do something about this?

Question

I am trying to explore JS classes and I am getting error if I am not calling super().

ReferenceError: Must call super constructor in derived class before accessing 'this' or returning from derived constructor

My requirement is that I just want to call the constructor of the child class. Can I do that?

class Employee {
  constructor() {
    console.log("I am an employee")
  }
}

class Learner extends Employee {
  constructor() {
    console.log("I am a learner")
  }
}

var learner = new Learner();

Answer 1

This is not possible and goes against OOP principles.

To access the same methods and properties in both Employee and Learner without invoking the other's constructor, create a parent class named something like "Person" with separate constructors for Employee and Learner.

So, Employee extends Person and Learner extends Person. Then, place the shared methods and attributes inside Person.