Show box if radio button checked using jQuery

Question

I have the following code:

    <fieldset>
        <legend>Do you currently have SolidWorks</legend>

        <ul>
            <li><label for=""><input type="radio" name="solidworks" value="Yes" id="rdYes" /> Yes</label></li>
            <li><label for=""><input type="radio" name="solidworks" value="No" id="rdNo" /> No</label></li>
        </ul>
    </fieldset>

    <fieldset id="boxReseller" style="display:none;">
        <legend>Who is your SolidWorks reseller?</legend>
        <ul>
            <li><label for=""><input type="radio" name="reseller" value="Cad Connect" /> Cad Connect</label></li>
            <li><label for=""><input type="radio" name="reseller" value="Cadtek" /> Cadtek</label></li>
            <li><label for=""><input type="radio" name="reseller" value="CCSL" /> CCSL</label></li>
            <li><label for=""><input type="radio" name="reseller" value="Innova" /> Innova</label></li>
            <li><label for=""><input type="radio" name="reseller" value="NT CAD/CAM" /> NT CAD/CAM</label></li>
            <li><label for=""><input type="radio" name="reseller" value="Solid Engineer" /> Solid Engineer</label></li>
            <li><label for=""><input type="radio" name="reseller" value="Solid Solutions Ireland" /> Solid Solutions Ireland</label></li>
            <li><label for=""><input type="radio" name="reseller" value="Solid Solutions Management" /> Solid Solutions Management</label></li>
            <li><label for=""><input type="radio" name="reseller" value="TMS Scotland" /> TMS Scotland</label></li>
        </ul>

    </fieldset>

What I want to do is hide the second fieldset by default and if a person chooses Yes then the box will appear, and if they choose No or Yes is not selected then the box will hide again.

Can anyone help? Thanks.

Answer 1

Ref Nick Craver - Nice solution although it is more felxaible as below

  $("input[name='solidworks']").change(function() {
    $("#boxReseller").toggle();
 });​​​​​​
$("input[name='solidworks']:checked").change(); //trigger correct state onload

By leaving the toggle as a wild card (undefined whichever terminology you prefer) I found it worked more efficiently. Nice though, thanks :)