C language pattern with unexpected result

Question

I am trying to create a program in C to draw this pattern :

1 1 2 1 3 1
1 2 2 2 3 2
1 3 2 3 3 3
1 4 2 4 3 4
1 5 2 5 3 5

I checked the answer from solutions.

#include <stdio.h>

int main ()
{
    int i;
    int j;
    
    for (i = 1 ; i <= 5 ; i++)
    {
        for (j = 1 ; j <= 3 ; j++)
        {
            printf("%i %i",j,i);
        }
        printf("\n");
    }
    
    return 0;

but I can't understand why this code (Above) gives the previous result instead of this result :

1 2 3 1
1 2 3 2
1 2 3 3
1 2 3 4
1 2 3 5

Answer 1

1 2 3 1
1 2 3 2
1 2 3 3
1 2 3 4
1 2 3 5

This output would appear if each iteration of the inner loop printed the value of j (1, 2, 3), and then, just after the inner loop, the value of i were printed. However, that is not what the code says. The inner loop contains printf("%i %i",j,i);, and that prints two numbers each time it is called, one for j and one for i.

To print the value for i separately after all the values for j, you would need a separate printf, as in:

    for (i = 1 ; i <= 5 ; i++)
    {
        for (j = 1 ; j <= 3 ; j++)
        {
            printf("%i ", j);
        }
        printf("%i\n", i);
    }