How to get a file's name without its extension or to load the entire path with the file without the file's extension?

Question

I have the following following String Array:

from tkinter import filedialog as fd

pathName = fd.askopenfilename(filetypes=[('Python file','*.py')])

Output

#pathName = 'C:\Users\User\Desktop\my_program.py  

Is there a way to extract the name of my file? In this example I would want the output to be "my_program"

Or a better solution for me would be to load directly file path without the file's extension. I need ti pathName to be 'C:\Users\User\Desktop\my_program'

I tried using tkinter's fd.askopenfilename but it always gets the file extension too.

Answer 1

You can use pathlib.Path() to work with path

import pathlib 

p = pathlib.Path(r'C:\Users\User\Desktop\my_program.py')

print( p.stem )    # 'C:\Users\User\Desktop\my_program'
print( p.parent )  # 'C:\Users\User\Desktop'
print( p.suffix )  # '.py'

you can also use / to create new path

print( p.parent / 'subfolder' / 'new.py' )  
# 'C:\Users\User\Desktop\subfolder\new.py'

Doc: pathlib