Sympy breaks regex in python?

Question

I have the code:

import re
import math
#from sympy import * # breaks?
#x, y, z = symbols('x y z')
#init_printing(use_unicode=True)


def evaluate_expression(expr, variables):
    # Evaluate the expression using eval(), and provide the variables dictionary
    return eval(expr, variables)

def main():
    tools = """
<<<[eval("5"),a_x]>>>
<<<[eval("5+a_x"),ans]>>>
"""

    variables = {}
    lines = tools.strip().split("\n")

    for line in lines:
        # Extract the inner array using regular expression
        match = re.search(r'<<<\[(.*?),(\w+)\]>>>', line)
        if match:
            # Extract expression and variable name
            expr = match.group(1)
            var_name = match.group(2)

            # Evaluate expression
            value = evaluate_expression(expr, variables)

            # Update variables dictionary
            variables[var_name] = value

            # Check if 'ans' is defined
            if 'ans' in variables:
                print("ans =", variables['ans'])
                break

if __name__ == "__main__":
    main()

If I dont import sympy, it runs fine, but if I do import sympy, it breaks, the re search no longer exists, no matter what I name variables. I dont get it?

Answer 1

sympy has re class, when you import all * you hide the re import. Import sympy first (or import only what you actually need from it)

from sympy import *
import re

# Output: ans = 10