How can I make it so that when I click an icon, a window with information appears?

There is an icon in the program; by clicking on it, a window with information should appear on top of the program. How can this be implemented?

import flet as ft

def main(page: ft.page):
    page.title = "Тренировка интуиции"
    page.window_width = 400.00
    page.window_height = 500.00
    page.window_resizable = False

    def info(e):
        # info text
        pass


    page.add(ft.Row([ft.IconButton(ft.icons.HELP, on_click=info)], alignment=ft.alignment.center))

ft.app(target=main)

Please tell me, I’ve been studying recently

Solution

import flet as ft

def main(page: ft.page):
    page.title = "Тренировка интуиции"
    page.window_width = 400.00
    page.window_height = 500.00
    page.window_resizable = False

Build info dialog with using AlertDialog. Add action to close your dialog. Content is the main content in pop-up.

    def info(e):
        diaolog = ft.AlertDialog(title=ft.Text("Information"),
            content=ft.Text("Test Text"),
            actions=[ft.TextButton(text="Close", on_click=close_diaolog)],
            open=True,
            
        )
        
        page.dialog = diaolog 
        page.update()

Built close_diaolog to close dialog after click Close.

    def close_diaolog(e):
        page.dialog.open = False
        page.update()
        
    page.add(ft.Row([ft.IconButton(ft.icons.HELP, on_click=info)], alignment=ft.alignment.center))

        
ft.app(target=main)