How can I convert base 10 integers to base 80 in Python without encountering IndexError?

Question

I'm working on a Python script where I need to convert base 10 integers to base 80 using a specific set of characters. I've implemented a function for this purpose, but I keep encountering an IndexError due to the index going out of range. Here's the function I'm using:

def base10_to_base80(n):
    base_80 = '0123456789abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ-_.~!$&\'()*+,:;=/'  # Corrected string
    if n == 0:
        return base_80[0]
    digits = []
    while n:
        digits.append(base_80[n % 80])
        n //= 80
    return ''.join(digits[::-1])

# Example usage:
decimal_number = 79
base_80_number = base10_to_base80(decimal_number)
print(base_80_number)

Answer 1

You are getting this error because

base_80 = '0123456789abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ-_.~!$&\'()*+,:;=/

len(base_80) is 79

you need one more character in base_80 to make it work properly.

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Your current code will work for base 79 you can just modify:

digits.append(base_80[n % 79])
        n //= 79

your code will work good.