How to use quotation mark in grep range query

How to find (f' or (f" or (" or (' with grep?

For example the regex could be (f\?["'] but how to pass this to grep - it can't be surrounded by quotation marks neither by apostrophes?

Solution

This pattern in your question f\?["'] matches an f char followed by ? and one of " or '

If the text is for example in file, you might use:

grep -Eo "(\(|\bf)['\"]" file

The pattern matches:

( Start group
- \( Match (
- | Or
- \bf A word boundary followed by matching f
) Close the group
['\"] Match either ' or "

Output

f'
f"
("
('