How to call positional arguments explicitly from function call

I have a function with positional arguments. as the function is more complex (this is only to show you my purpose), i want to explicitly write in the function call the name of the arguments.

def my_function(a, b, *other):
    print(a)
    print(b)
    for item in other:
        print(item)

I want to avoid writing:

my_function(1, 2, 4,5,6)

and write it like:

my_function(a=1, b=2, other=*[4,5,6])

python (3.x) does not allow writing things like my_function(a=1, b=2, 4,5,6) . we get this error because of the mapping SyntaxError: positional argument follows keyword argument

is there any way i could mention "other" in the signature ? it seems like all names of arguments must be named or nothing.

thanks if you have any tip.

Solution

No, once you use the first keyword argument when calling, all following arguments must be keyword arguments.

You cannot explicitly set the value to be assigned to the *args or **kwargs parameter, they will be collected according to the callers usage, E.g.,

def f(*args, **kwargs):
  print(f"{args=} {kwargs=}")

>>> f(args="a", kwargs="b")
args=() kwargs={'args': 'a', 'kwargs': 'b'}

An alternative may be to have other take a list of values, instead of using *args.