Make file with if else condition inside the for loop

Question

I am trying to loop using "for" inside the directory (dir) and building a go code and then checking with if dir name is equal to dir/task1 or dir/task2, is yes the zip the resource/ directory along with bootstrap else zip only bootstrap.

When I do make build, I see it is not going to else condition, please help

build:
    for directory in $$(find dir -mindepth 1 -maxdepth 1 -type d) ; \
        do env GOOS=linux go build -ldflags="-s -w" -o "bootstrap" $${directory}/main.go ; \
            if [ $${directory}='dir/task1' ] || [ $${directory}='dir/task2' ]; then \
                zip -r $${directory}.zip bootstrap resources/ ; \
            else \
                zip $${directory}.zip bootstrap ; \
            fi \
        done

Answer 1

That || in the if clause is a bashism — that is, it will fail for many Unix shells other than GNU Bash. Also, it worth explicitly passing -print to find as not all implementations of it default to printing when no explicit action was specified in the call.

With these two fixed, the thing appears to work for me:

$ cat Makefile 
all:
    for directory in $$(find dir -mindepth 1 -maxdepth 1 -type d -print); do \
        echo $${directory}; \
        if [ $${directory} = 'dir/task1' -o $${directory} = 'dir/task2' ]; then \
            echo "\tif branch"; \
        else \
            echo "\telse branch"; \
        fi; \
    done

$ mkdir -p dir/{task1,task2,task3,task4}
$ make --trace all
Makefile:2: target 'all' does not exist
for directory in $(find dir -mindepth 1 -maxdepth 1 -type d -print); do \
    echo ${directory}; \
    if [ ${directory} = 'dir/task1' -o ${directory} = 'dir/task2' ]; then \
        echo "\tif branch"; \
    else \
        echo "\telse branch"; \
    fi; \
done
dir/task1
    if branch
dir/task3
    else branch
dir/task4
    else branch
dir/task2
    if branch
$