Is there a way to orderby using a value from a different array

Question

Hey so i have one array with data like this

arr1 = [
{mood: "good", name: "Jake"},
{mood: "good", name: "Jill"},
{mood: "good", name: "Jack"}
]

and another array

arr2 = [
{number: 2, name: "Jake"},
{number: 1, name: "Jill"},
{number: 3, name: "Jack"}
]

I was looking to sort array one using the number from array 2. So, basically I would need to use a filter to match the name from arr1 to arr2 and then get the number from the resulting array and sort.

How can I get this done ?

arr1.sort((a: any, b: any) => arr1.filter((item: { name: string; }) => item.name == arr2[i].name));

I am totally lost, so much so, I may not have asked a proper question !

Answer 1

You could simply use an object for the order of name and take the value for sorting.

const
    arr1 = [{ mood: "good", name: "Jake" }, { mood: "good", name: "Jill" }, { mood: "good", name: "Jack" }],
    arr2 = [{ number: 2, name: "Jake" }, { number: 1, name: "Jill" }, { number: 3, name: "Jack" }],
    order = Object.fromEntries(arr2.map(({ name, number }) => [name, number]));

arr1.sort((a, b) => order[a.name] - order[b.name]);

console.log(arr1);

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Sorting by index. arr2 has a different order than above.

const
    arr1 = [{ mood: "good", name: "Jake" }, { mood: "good", name: "Jill" }, { mood: "good", name: "Jack" }],
    arr2 = [{ number: 1, name: "Jill" }, { number: 2, name: "Jake" }, { number: 3, name: "Jack" }],
    order = Object.fromEntries(arr2.map(({ name }, index) => [name, index + 1]));

arr1.sort((a, b) => order[a.name] - order[b.name]);

console.log(arr1);

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