This is the code that I am trying to run -
#include <stdio.h>
int main()
{
char a;
int b;
printf("Name of Prisoner\n");
scanf("%c" ,a);
printf("How many years in jail as stated by the court?\n");
scanf("%d", b);
printf("Prisoner "a" goes to jail for "b" years\n"a,b);
return 0;
}
This is the Error shown -
P.c: In function 'main':
P.c:14:23: error: expected ')' before 'a'
printf("Prisoner "a" goes to jail for "b" years\n"a,b);
^
As you can see I am at a very beginner level at C or any programming language. I want to collect the name of the prisoner and the years of prison sentenced to him and simply print a statement which includes the data collected. But it is not being compiled. The error is given. I am pretty sure it's a very small and simple fix but I am trying to run a little bit ahead of my classes and don't have any personal guide or teacher with me. Can anyone please educate me on this issue?
Kindly note that the statement printf("Prisoner "a" goes to jail for "b" years\n"a,b); contains an error, indicative of a common mistake made by beginner programmers. I encourage you to thoroughly review the error message provided, aiming to comprehend its nuances and rectify similar errors in the future. Additionally, investing time in studying format specifiers in C will enhance your understanding of proper usage in print and scan statements, contributing to more robust and error-free code.Websites like Format specifiers in C helps you to move on from the beginner level.
#include <stdio.h>
int main()
{
char a[10]; //Use character array for declaring sequence of character
int b;
printf("Name of Prisoner\n");
scanf("%s" ,a);
printf("How many years in jail as stated by the court?\n");
scanf("%d", &b);
printf("Prisoner %s goes to jail for %d years\n",a,b);
return 0;
}
output:
Name of Prisoner
Mike
How many years in jail as stated by the court?
4
Prisoner Mike goes to jail for 4 years
And while learning about arrays, Additionally go through the similar of Arrays and pointers C pointers and arrays