'ELSE' Running even if 'If' is true

Question

I was Trying to Make a Simple Maths Calculator.

pi = math.pi
e = math.e
φ = 1.618033988749895

while True:
    sh= input("MATHS CALCULATOR: ")

    if sh== "Values":
        va=input("NAME OF VALUE: ")
        if va=="pi":
            print("PI value is", pi)

        elif va=="PI":
            print("PI value is", pi)

        elif va=="e":
            print("Euler's Number(e) value is", e)

        elif va=="g":
            print("Golden Ratio(φ) value is", φ)

        else:
            print("Try Another")

    if sh== "Simple":
        sim=input("ENTER AN OPERATOR: ")
        a=int(input("ENTER FIRST NUMBER: "))
        b=int(input("ENTER SECOND NUMBER: "))
        if sim=="+":
            c=a+b
            print(a,"PLUS",b,"EQUALS",c)
        elif sim=="*":
            c=a*b
            print(a,"TIMES",b,"EQUALS",c)
        elif sim=="x":
            c=a*b
            print(a,"TIMES",b,"EQUALS",c)
        elif sim=="/":
            c=a/b
            print(a,"BY",b,"EQUALS",c)
        elif sim=="-":
            c=a-b
            print(a,"MINUS",b,"EQUALS",c)
        else:
            print("Try Another")

    if sh=="Stop":
        print("Thanks For Using!")
        quit()

    else:
        print("Check Again the Spelling!")

I tried Everything from changing The entire Program. I also Tried to Remove the loop, Nothing Worked. All lead to this. (https://i.sstatic.net/xUVXP.png) I expect the code to only Show the 'ELSE' message when Nothing Matches.

Answer 1

the main ifs are uncorrelated in that way, meaning that every one is checked separately from the others. The last else is only combined with the last if. To solve your problem, you should do something like this:

pi = math.pi
e = math.e
φ = 1.618033988749895

while True:
    sh= input("MATHS CALCULATOR: ")

    if sh== "Values":
        va=input("NAME OF VALUE: ")
        if va=="pi":
            print("PI value is", pi)

        elif va=="PI":
            print("PI value is", pi)

        elif va=="e":
            print("Euler's Number(e) value is", e)

        elif va=="g":
            print("Golden Ratio(φ) value is", φ)

        else:
            print("Try Another")

    elif sh== "Simple":
        sim=input("ENTER AN OPERATOR: ")
        a=int(input("ENTER FIRST NUMBER: "))
        b=int(input("ENTER SECOND NUMBER: "))
        if sim=="+":
            c=a+b
            print(a,"PLUS",b,"EQUALS",c)
        elif sim=="*":
            c=a*b
            print(a,"TIMES",b,"EQUALS",c)
        elif sim=="x":
            c=a*b
            print(a,"TIMES",b,"EQUALS",c)
        elif sim=="/":
            c=a/b
            print(a,"BY",b,"EQUALS",c)
        elif sim=="-":
            c=a-b
            print(a,"MINUS",b,"EQUALS",c)
        else:
            print("Try Another")

    elif sh=="Stop":
        print("Thanks For Using!")
        quit()

    else:
        print("Check Again the Spelling!")

In this way, only one of the sh ==/else condition is accepted.