Search code examples
typescripteslinttypescript-eslint

Can we disallow to use || on optional types by lint?


I want to disallow following code:

function(num: undefined|number) {
  return num || 10;
}

I want use ?? instead of ||.


Solution

  • You can use the rule @typescript-eslint/prefer-nullish-coalescing:

    This rule reports when you may consider replacing:

    • An || operator with ??
    • An ||= operator with ??=

    Also note that the rule documentation states:

    CAUTION

    This rule will not work as expected if strictNullChecks is not enabled.

    To enable it add "@typescript-eslint/prefer-nullish-coalescing": "error" to the rules in the linter configuration.

    Read the documentation page for additional configuration options for the rule.