List comparison "==" vs "in" with elementtree

Question

I have an XML I am parsing, and two elements have the same name, but require a unique value for each out of two options. I am able to get the code to function as I would like, however I am not sure why one method works (in) and the other does not (==).

XML snippet:

<metaMetadata>
    <metadataSchema>Value1</metadataSchema>
    <metadataSchema>Value2</metadataSchema>
</metaMetadata>

code:

schema_val = ['Value1', 'Value2']

for ele in root.findall(".//{*}metaMetadata"):
    m_schema = ele.findall("lom:metadataSchema",ns)

    m_schema_check = [i for i in schema_val if i in m_schema[0].text]
    if m_schema_check:
        for i in m_schema_check:
            schema_val.remove(i)
            if m_schema[1].text in schema_val:
                print('pass')

This works as I would like it to, but I am trying to understand why it only works when I have in , and when I have == the code doesn't function and skips the print.

Answer 1

Edit: Would you like compare xml list values with your schema value list? If the order of the list elements doesn't matter you can sort() the lists before comparison:

import xml.etree.ElementTree as ET

xml_str = """<metaMetadata>
    <metadataSchema>Value1</metadataSchema>
    <metadataSchema>Value2</metadataSchema>
</metaMetadata>"""

tree = ET.fromstring(xml_str)

l = [c.text for c in tree.findall('.//metadataSchema')]

schema_val = ['Value2', 'Value1']
if l.sort() == schema_val.sort():
    print('true')
else:
    print('false')

Output: true