How to run a program by default app in python

Question

I need to start my app with python by defalut. Like double-clicking on them.

I know there is subprocess.Popen("program", "file") but I need to start app by default and I don't know with what program I need to start app.

Answer 1

for windows you can use os.startfile(FILEPATH) and for macOS you can use subprocess.call(('open', FILEPATH))

and for all systems this code is useful:

import platform
import os

if platform.system() == 'Darwin':       # macOS
    subprocess.call(('open', FILEPATH))
elif platform.system() == 'Windows':    # Windows
    os.startfile(FILEPATH)
else:                                   # linux variants
    subprocess.call(('xdg-open', FILEPATH))