Python parse yaml file

Question

I have yaml file and I want to get specific set of key-value pairs. How I can do that?

DEV:
  A: "A_DEV_config.xml"
  B: "B_DEV_config.xml"
  C: "C_DEV_config.xml"
PROD:
  D: "D_PROD_config.xml"
  E: "E_PROD_config.xml"
  F: "E_PROD_config.xml"
OTHERS:
  G: "G_config.xml"
  H: "H_config.xml"
  K: "K_config.xml"

I want to get something like this:

if I check DEV == true:

output list of keys ->  A,B,C,G,H,K

if I check PROD == true:

output list of keys ->  D,E,F,G,H,K

As you may have noticed, I need to get OTHERS in both cases.

I tried to use code:

stream = open(yml_file, 'r')
data = yaml.safe_load(stream)
print(data.get("DEV").keys())

But I don't know how to concatenated it together

Answer 1

To concatenate the keys (DEV or PROD) with the keys from the OTHERS section, you need to define a function to fetch the keys based on the environment and concatenate with OTHERS either way.

Below I have written a function:

import yaml

with open(yml_file, 'r') as stream:
    data = yaml.safe_load(stream)

def get_keys(environment):
    env_keys = list(data.get(environment, {}).keys())
    others_keys = list(data.get("OTHERS", {}).keys())
    return env_keys + others_keys

if DEV == True:
    print(get_keys("DEV"))
elif PROD == True:
    print(get_keys("PROD"))

Hope this helps!