Replacing the text that follows a given word

Question

I need help with replacing the first line in the file that follows a given word (which will not be repeated).
I have a file with content:

"text1"
{
    "text2" "0"
    "text3" "0"
    "text4" "0"
    "text5" "0"
    "text6" "0"
}
"text11"
{
    "text2" "0"
    "text3" "0"
    "text4" "0"
    "text5" "0"
    "text6" "0"
}
"text21"
{
    "text2" "0"
    "text3" "0"
    "text4" "0"
    "text5" "0"
    "text6" "0"
}

I would like to replace in Bash the line containing "text 5.0", but only the first one after the "text11" line.
To finally get the result:

"text1"
{
    "text2" "0"
    "text3" "0"
    "text4" "0"
    "text5" "0"
    "text6" "0"
}
"text11"
{
    "text2" "0"
    "text3" "0"
    "text4" "0"
    "REPLACED TEXT" "1"
    "text6" "0"
}
"text21"
{
    "text2" "0"
    "text3" "0"
    "text4" "0"
    "text5" "0"
    "text6" "0"
}

Thanks for the help.

Answer 1

With GNU sed:

sed '/^"text11"/,/^}/s/"text5" "0"/"REPLACED TEXT" "1"/' file

Only in the area with a line starting (^) with "text11" and the next line starting with } replace "text5" "0" with "REPLACED TEXT" "1".

Output:

"text1"
{
    "text2" "0"
    "text3" "0"
    "text4" "0"
    "text5" "0"
    "text6" "0"
}
"text11"
{
    "text2" "0"
    "text3" "0"
    "text4" "0"
    "REPLACED TEXT" "1"
    "text6" "0"
}
"text21"
{
    "text2" "0"
    "text3" "0"
    "text4" "0"
    "text5" "0"
    "text6" "0"
}

---

See: The Stack Overflow Regular Expressions FAQ