How can I remove some objects contains on a js object according to a specified property?

Question

I have an object js that contains other objects like this :

const USER: {
        LANGUAGE: { 
            'editable': 1,
            'decimal': 0,
            'degree': 0,
            'master': 1,
            0: ['', '', 0],  
            1: ['', '', 1], 
        },
        LUM: { 
            'editable': 1,
            'decimal': 0,
            'degree': 0,
            'master': 0,
            0: ['', '', 0], 
            1: ['', '', 1], 
            2: ['', '', 2], 
        },
        SP: { 
            'editable': 1,
            'decimal': 0,
            'degree': 0,
            'master': 1,
            0: ['', '', 0], 
            1: ['', '', 1], 
            2: ['', '', 2], 
        },
    },
};

I want to create another object that contains only object which contains 'master': 1;

How can I do that?

Answer 1

You can try the following solutions:

const filteredObjects = {};

for (const key in USER) {
    if (USER[key]['master'] === 1) {
        filteredObjects[key] = USER[key];
    }
}

console.log(filteredObjects);

or the approach using Object.keys and the array methods filter and reduce.

const filteredObjects = Object.keys(USER)
    .filter(key => USER[key]['master'] === 1)
    .reduce((result, key) => {
        result[key] = USER[key];
        return result;
    }, {});

console.log(filteredObjects);