How to match typescript Record value with the key?

Question

interface User {
  email: string;
  name: string;
}

const UserRecord = Record<keyof User, keyof User> {
  email: 'email',
  name: 'name',
};

My problem with the above code that it's not typesafe for the values, so I could even do:

const UserRecord = Record<keyof User, keyof User> {
  email: 'name',
  name: 'email',
};

Answer 1

You can use mapped types:

interface User {
  email: string;
  name: string;
}

const UserRecord: {
  [x in keyof User]: x
} = {
  email: 'email',
  name: 'name',
};