When compiling this code
#include <math.h>
double *y0;
int main()
{
return 0;
}
with gcc 13.2.0
from latest debian-sid, I get the following error:
gcc -o a.out proof.c -Wall -lm
proof.c:3:9: error: 'y0' redeclared as different kind of symbol
3 | double *y0;
| ^~
In file included from /usr/include/features.h:490,
from /usr/include/x86_64-linux-gnu/bits/libc-header-start.h:33,
from /usr/include/math.h:27,
from proof.c:1:
/usr/include/x86_64-linux-gnu/bits/mathcalls.h:223:1: note: previous declaration of 'y0' with type 'double(double)'
223 | __MATHCALL (y0,, (_Mdouble_));
| ^~~~~~~~~~
make: *** [Makefile:6: proof] Error 1
Note that if I replace *y0
with a different name, e.g. *x0
, it does not complain.
Clearly there's a conflict of names with mathlib
, but is this normal? should such kind of conflict be possible or is it a bug?
y0
is the name of a Bessel function implemented in the math library. You should not use this name for a global variable.
Here is a list of the Bessel functions supported by most C math libraries, albeit not part of the C Standard as of C23:
// Bessel functions of the first kind
double j0(double);
double j1(double);
double jn(int, double);
// Bessel functions of the second kind
double y0(double);
double y1(double);
double yn(int, double);
These functions have been part of the POSIX Standard since the beginning, they have been available on Unix since System V in 1983. The GNU math library for C supports them by default, along with many other extensions, but as they are not part of Standard C, the declarations are conditional in <math.h>
and omitted if strict standard conformance is requested with a compiler option (-std=c89
, -std=c99
, -std=c11
, etc.).