Double to Int with removing precision point dynamically

Question

Is there a way in Kotlin, or Java to parse Double to Int knowing that all the doubles will not exceed the Int memory limit? examples:

Double	Int
1,123	1123
1,1	11
1,12345	11234
0,12345	1234

I know we can parse it to string first and remove the '.' and then to Int but I want a more effective way.

Answer 1

Assuming that you want to keep all the significant digits you should use BigDecimal to do the conversion and transformation without missing information:

import java.math.BigDecimal;

public class MyClass {
    public static void main(String args[]) {
      BigDecimal x=BigDecimal.valueOf(1.12345);
      int y=x.unscaledValue().intValueExact();
      System.out.println("y = " + y);
    }
}

Output:

y = 112345

valueOf() is needed to create a BigDecimal from a floating point type without representation errors. intValueExact() will throw an exception if the result is out of range for an int.

Note that this solution keeps the 5 at the end of the number unlike your example.