i have arg.yml file with
filename : 'custom_file_name'
data1 : 5028
data2 : 1111
...
and script.py which saves an output file named output.txt
from jinja2 import Environment, FileSystemLoader
import yaml
env = Environment(loader=FileSystemLoader("."))
templ = env.get_template("template.txt")
with open('arg.yml') as f:
arg = yaml.safe_load(f)
with open("output.txt", 'w') as f:
f.write(templ.render(arg))
how to rename output.txt to file with variable name filename from arg.yaml
to custom_file_name.txt
you could just :
...
with open(f"{arg["filename"]}.txt", 'w') as f:
f.write(templ.render(arg))