So I've written a basic type tagging structure:
struct TypeTag
{
inline static size_t counter = 0;
template<typename T>
static size_t get()
{
static size_t value = counter++;
return value;
}
};
class c1 {};
class c2 {};
class c3 {};
class c4 {};
int main()
{
std::cout << "c1: " << TypeTag::get<c1>() << '\n';
std::cout << "c2: " << TypeTag::get<c2>() << '\n';
std::cout << "c3: " << TypeTag::get<c3>() << '\n';
std::cout << "c4: " << TypeTag::get<c4>() << '\n';
std::cout << "\n================================\n\n";
std::cout << "c1: " << TypeTag::get<c1>() << '\n';
std::cout << "c2: " << TypeTag::get<c2>() << '\n';
std::cout << "c3: " << TypeTag::get<c3>() << '\n';
std::cout << "c4: " << TypeTag::get<c4>() << '\n';
return 0;
}
Output:
c1: 0
c2: 1
c3: 2
c4: 3
================================
c1: 0
c2: 1
c3: 2
c4: 3
This will associate a type to a value.
Here's a working example of it: https://godbolt.org/z/9rqK6Pasz
Suppose we know the value at compile time: template <size_t value>
; is there any way to do the opposite? Is there any way to associate a variable value to a type?
template <size_t value>
struct TypeFrom
{
using type = ... // SOMETHING HERE
};
As shown, this is not possible for some fairly fundamental reasons: C++ simply does not work this way.
The value of TypeTag::get<T>
is known only at runtime. The value for a given T
depends on the order of the first call to a template instance for this particular T
relative to first calls for other types. It's entirely possible that each time the program runs the same types get different TypeTag
s. This is fundamental to C++: a static
ally-scoped object is constructed the first time its scope gets entered. The fact that the scope is generated from a template is immaterial. Effectively counter++
gets evaluated, to initialize the static size_t value
the first time its get()
gets called.
So, when all is said and done, a particular TypeTag::get<T>
value is known only at runtime.
But templates parameters (such as the size_t n
in ValueType<n>
) must be known at compile time. This is fundamental to C++. The End.