How to define multi type as one type in golang

Question

func GetFailedReasonAndErr (xxx) (string, error){
...
}

func AnyFailed (args ...(string, error)) {
   for _, arg := range args {
      if arg.error != nil {
         return arg
       }
   }
}

func main () {
    reason, err := AnyFailed(GetFailedReasonAndErr(yyy), GetFailedReasonAndErr(zzz))
    println(reason, err)
}

code above is unable to be complied, because "args ...(string, error)" is not allowed. can I define (string, error) as one type ? or any better way ?(may use struct?) like : type reasonAndError (string, error)

Answer 1

can I define (string, error) as one type ?

No, not with that syntax. Go does not have tuples.

(may use struct?) like : type reasonAndError (string, error)

Yes, declare a struct type and use that. The syntax for declaring struct types is as follows:

type reasonAndError struct {
    reason string
    err    error
}

Then, to use it, you can do:

func GetFailedReasonAndErr(xxx) reasonAndError {
    // ...
}

func AnyFailed(args ...reasonAndError) (string, error) {
   for _, arg := range args {
      if arg.err != nil {
         return arg.reason, arg.err
       }
   }
   return "", nil
}

func main () {
    reason, err := AnyFailed(GetFailedReasonAndErr(yyy), GetFailedReasonAndErr(zzz))
    println(reason, err)
}