Instagram python request to get access_token

Question

I want to create instagram authentication using a python request to get an access token

router = APIRouter(prefix="/meta/instagram", tags=["instagram"])

SCOPE = 'instagram_graph_user_profile,instagram_graph_user_media'

@router.get("/auth")
async def login(request: Request):
    state = secrets.token_hex(16)
    auth_url = 'https://api.instagram.com/oauth/authorize'
    payload = {
        'client_id': config.id_app_ig,
        'redirect_uri': config.redirect_uri_ig,
        'response_type': 'code',
        'state': state,
        'scope': SCOPE
    }
    complete_url = auth_url + urlencode(payload)
    return RedirectResponse(complete_url)

@router.get("/auth2callback")
async def token(code: str):
    token_url = 'https://api.instagram.com/oauth/access_token'
    payload = {
        'client_id': config.id_app_ig,
        'redirect_uri': config.redirect_uri_ig,
        'client_secret': config.secret_app_ig,
        'code': code
    }
    get_access_token = requests.post(token_url, data=payload)
    access_token = get_access_token.json().get("access_token")
    return JSONResponse (access_token)

but always error like this:

can somebody help me with this eror

Answer 1

You've missed adding the ? sign after /authorize. Hence, the URL to get the Authorization Code should look like this:

https://api.instagram.com/oauth/authorize?client_id...
                                         ^

I would highly suggest using httpx instead of requests to make HTTP requests within a FastAPI async def endpoint. Please have a look here and here for more details.