I am trying to learn the Swift Regex Builder. The string I am working with contains values as follows: x,xxx,xxx. I can capture the value as a string with capture and transform but would like to output an integer instead. Is there a way to access the values obtained by the Repeat statements in my capture block and convert them to one integer value? Below is my test function.
func Test() {
let stringData = "<tr class=BdT Bdc($seperatorColor) Ta(end) Fz(s) Whs(nw)><td class=Py(10px) Ta(start) Pend(10px)><span>Jun 30, 2023</span></td><td class=Py(10px) Pstart(10px)><span>405.40</span></td><td class=Py(10px) Pstart(10px)><span>408.22</span></td><td class=Py(10px) Pstart(10px)><span>405.29</span></td><td class=Py(10px) Pstart(10px)><span>407.28</span></td><td class=Py(10px) Pstart(10px)><span>407.28</span></td><td class=Py(10px) Pstart(10px)><span>5,160,100</span></td></tr><tr class=BdT Bdc($seperatorColor) Ta(end) Fz(s) Whs(nw)><td class=Py(10px) Ta(start) Pend(10px)><span>Jun 29, 2023</span></td><td class=Py(10px) Pstart(10px)><span>400.60</span></td><td class=Py(10px) Pstart(10px)><span>402.67</span></td><td class=Py(10px) Pstart(10px)><span>400.19</span></td><td class=Py(10px) Pstart(10px)><span>402.51</span></td><td class=Py(10px) Pstart(10px)><span>402.51</span></td><td class=Py(10px) Pstart(10px)><span>3,914,800</span></td></tr><tr class=BdT Bdc($seperatorColor) Ta(end) Fz(s) Whs(nw)><td class=Py(10px) Ta(start) Pend(10px)><span>Jun 28, 2023</span></td><td class=Py(10px) Pstart(10px)><span>401.35</span></td><td class=Py(10px) Pstart(10px)><span>403.49</span></td><td class=Py(10px) Pstart(10px)><span>400.71</span></td><td class=Py(10px) Pstart(10px)><span>402.55</span></td><td class=Py(10px) Pstart(10px)><span>400.97</span></td><td class=Py(10px) Pstart(10px)><span>4,320,700</span></td></tr>"
let StartingSeperator = Regex {"<td class=Py(10px) Ta(start) Pend(10px)><span>"}
let InterValueSeperator = Regex {"</span></td><td class=Py(10px) Pstart(10px)><span>"}
let EndingSeperator = Regex {"</span>"}
let CaptureDollarValue = Regex {
TryCapture {
OneOrMore(.digit)
"."
Repeat(.digit, count: 2)
} transform: {
Double($0)
}
}
let tradingDayPattern = Regex {
StartingSeperator
Capture(.date(format: "\(month: .abbreviated) \(day: .twoDigits), \(year: .extended(minimumLength: 4))", locale: Locale(identifier: "en_US_POSIX") , timeZone: .gmt))
InterValueSeperator
CaptureDollarValue
InterValueSeperator
CaptureDollarValue
InterValueSeperator
CaptureDollarValue
InterValueSeperator
CaptureDollarValue
InterValueSeperator
CaptureDollarValue
InterValueSeperator
//#########################################################################################
Capture {
Repeat(1...3) {
One(.digit)
}
","
Repeat(count: 3) {
One(.digit)
}
","
Repeat(count: 3) {
One(.digit)
}
} transform: {
String($0). // this is where I would like to output an integer
}
//#########################################################################################
EndingSeperator
}
for match in stringData.matches(of: tradingDayPattern) {
let (_, date, _, _, _, close, _, v1) = match.output
print("\(date) - \(close) - \(v1)")
}
} // end testing function
If it is always a well-formed number (i.e. comma separator every 3 digits, and nothing like 1,2,3 etc), then you can use an IntegerFormatStyle, similar to what you did when capturing the date.
Capture(IntegerFormatStyle<Int>(locale: Locale(identifier: "en_US_POSIX")))
You should specify an appropriate locale.
If the number can be something weird like 1,2,3, then you can replace the commas and convert it to an Int:
transform: {
Int($0.replacing(",", with: ""))
}
Note that this produces an optional Int?.