Reading a text file column wise and count which column it is written in Python

Question

A text file contains:

//     H HGD
//     i eoa
//       loy
//       ld
//       o
//       _
//       W
//       o
//       r
//       l
//       d

How can I put it on a list and add at which column it was written such that it outputs: [[<1st_word>,<location of the 1st word>],[<2nd_word>,<location of the 2nd word>],...]

So far I have written a code (shown below), but I'am stuck:

file = open(text_file, "r")
wrd = ""
for line in file: #Each line from file
    for c in ln: #Each character in line
        if(c != ' ' or c != '\n' or c != '/'): #Ignore slashes (/), white spaces, and newlines
            #list = put word on a list and count at which column was found
            #print(list)

How can I put it on a list and add at which column it was written, such that it outputs: [[Hi,8],[Hello_World,10],[Good,11],[Day,12]]

Answer 1

I have done this way:

1. creating a dictionary of which characters are observed in what index
2. reformatting into the list format specified in the question

results = {}
with open(text_file, "r") as fp:    
    for line in fp:
        for idx, c in enumerate(line):
            if c not in [' ', '\n', '/', '\t']:
                if idx not in results.keys():
                    results[idx] = []
                results[idx].append(c)

print(results)
#Out[6]: 
#{7: ['H', 'i'],
# 9: ['H', 'e', 'l', 'l', 'o', '_', 'W', 'o', 'r', 'l', 'd'],
# 10: ['G', 'o', 'o', 'd'],
# 11: ['D', 'a', 'y']}

final_results = [[''.join(v), k+1] for k,v in results.items()]
print(final_results)
# Out[10]: [['Hi', 8], ['Hello_World', 10], ['Good', 11], ['Day', 12]]

If the text has tabs as well, you can use Textwrap to translate them into whitespace:

import textwrap
wrapper = textwrap.TextWrapper()

results = {}
with open(text_file, "r") as fp:    
    for line in fp:
        for idx, c in enumerate(wrapper.wrap(line)[0]):
            if c not in [' ', '\n', '/']:
                if idx not in results.keys():
                    results[idx] = []
                results[idx].append(c)

#{8: ['H', 'i'],
# 10: ['H', 'e', 'l', 'l', 'o', '_', 'W', 'o', 'r', 'l', 'd'],
# 11: ['G', 'o', 'o', 'd'],
# 12: ['D', 'a', 'y']}

final_results = [[''.join(v), k] for k,v in results.items()]
print(final_results)
#[['Hi', 8], ['Hello_World', 10], ['Good', 11], ['Day', 12]]

You can do it without list comprehension as well:

final_results = []
for idx, char_vals in results.items():
    word = ''.join(char_vals)
    final_results.append([word, idx])
print(final_results)
#[['Hi', 8], ['Hello_World', 10], ['Good', 11], ['Day', 12]]