How to filter a list of objects by a list of ids?

Question

Let's say we have a list of objects like this:

my_objects = [
    {
        "id":0,
        "some_value":"a"
    },
    {
        "id":1,
        "some_value":"a"
    },
    {
        "id":2,
        "some_value":"b"
    },
    {
        "id":3,
        "some_value":"b"
    },
]

Given a list of ids like this:

ids = [1, 2]

What would be a pythonic way to retrieve a list of all the objects with the ids in this list? e.g.:

my_objects_filtered = [
    {
        "id":1,
        "some_value":"a"
    },
    {
        "id":2,
        "some_value":"b"
    }
]

What I want in the end is a list of the "some_value" value for all ids in the list "ids":

ids = [a, b]

Which I could get by doing this:

some_values = [my_object.param_id for my_object in my_objects_filtered]

But I do not know how to get my_objects_filtered Thanks in advance.

Answer 1

Something like the below

my_objects = [
    {
        "id": 0,
        "some_value": "a"
    },
    {
        "id": 1,
        "some_value": "a"
    },
    {
        "id": 2,
        "some_value": "b"
    },
    {
        "id": 3,
        "some_value": "b"
    },
]
ids = [1, 2]
final_list = [x['some_value'] for x in my_objects if x['id'] in ids]
print(final_list)

output

['a', 'b']