How can I run a linux command with brackes in Github workflow YAML?

Question

In a github workflow YAML, I've been trying several ways to run a command to remove all the content of a directory excluding a directory, and I don't find the way to make it work.

The command is: rm -rf !(dist)

It throws an error since brackets are special yaml characters, so I have to quote them rm -rf "!(dist)". Then Github workflow doesn't throw any error, but the command isn't working.

Some idea how can I make it work?

To give more context, I want to publish just the dist content of a NPM project, instead publishing the root of it including the dist folder.

This is the YAML:

name: Node.js Package

on:
  release:
    types: [created]

jobs:
  publish-gpr:
    runs-on: ubuntu-latest
    permissions: write-all
  steps:
    - uses: actions/checkout@v3
    - uses: actions/setup-node@v3
    with:
      node-version: 16
    - run: npm ci
    - run: npm run build
    - run: |
        rm -rf "!(dist)"
        cd dist
        cp -R ./ ../
        cd ..
        rm -rf ./dist
    - run: npm publish

Thanks in advance.

Answer 1

As @Azeem indicated in the comments, I had to add shopt -s extglob to the beggining of the script.

This is the working YAML with brackets:

name: Node.js Package

on:
  release:
    types: [created]

jobs:
  publish-gpr:
    runs-on: ubuntu-latest
    permissions: write-all
    steps:
      - uses: actions/checkout@v3
      - uses: actions/setup-node@v3
        with:
          node-version: 16
      - run: npm ci
      - run: npm run build
      - run: |
          shopt -s extglob
          rm -rf "!(dist)"
          cd dist
          cp -R ./ ../
          cd ..
          rm -rf ./dist
      - run: npm publish