(Swift) Confused between a return value of a for-in loop within a function, and a return value that comes after the loop (within the function))

Question

I am confused with the following code.

func allTestsPassed(tests: [Bool]) -> Bool {
    for test in tests {
        if test == false {
            return false
        }
    }
    return true
}

If the code within the if-else statement (within the for-in loop) executes, it returns false.

But the code following the for-in loop is: return true.

Two different boolean values returned within a function.

When I execute print(allTestsPassed([false])) it prints 'false'.

It seems to disregard the 'return true' that follows the loop.

I do not understand.

Answer 1

return stop the process there and don't execute anything after it. It simply stop the process there.

To understand more let's update logic and see results.

func allTestsPassed(tests: [Bool]) -> Bool {
    print("start of logic")
    var currentNumber : Int = 1
    for test in tests {
        print("currentNumber=\(currentNumber) with value==\(test)")
        if test == false {
            print("returning number because data is false")
            return false
        }
        currentNumber += 1
    }
    print("end of logic")
    return true
}

---

Case 1 : All input is true

Now let's try case 1 where all input will be true

allTestsPassed(tests: [true, true, true, true])

Results is

start of logic
currentNumber=1 with value==true
currentNumber=2 with value==true
currentNumber=3 with value==true
currentNumber=4 with value==true
end of logic

---

Case 2 : One of the input is false

allTestsPassed(tests: [true, true, false, true])

Result is

start of logic
currentNumber=1 with value==true
currentNumber=2 with value==true
currentNumber=3 with value==false
returning number because data is false

---

If you see in second case you don't see end of logic because it do the return when test=false

Hope the logs will clears your understanding...