I have a string like this:
hello item:::::405498:::244405553::3405:34:405:59:::445:447:3205:::[test] and another 405 with test
I need to catch the last part of the string ignoring :
as delimiter.
In my specific case I need to find the last 405
ignoring the :405498:
:244405553:
:3405:
and :405:
that comes first
I'm really rookie with Lua and so far I have tried to match with :(.-):
but I think I'm really far away from the correct solution
To find last number in the string ignoring surrounded with colons:
s = "hello item:::::405498:::244405553::3405:34:405:59:::445:447:3205:::[test] and another 405 with test"
print(s:match".*%f[%d:](%d+)%f[^%d:]") --> 405