C programming Patterns to print the following pattern

Question

i had try to print the following pattern but i only able to decrease the letters from the one side but not from both the side

Please someone help me with this : to print this pattern

this is the code that i use:

#include <stdio.h>
#include <string.h>

int main() {
   char str[] = "Programming";
   int len = strlen(str);

   for (int i = 0; i < len; i++) {
      for (int j = i; j<len; j++) {
              printf("%c", str[j]);
      }
      printf("\n");
   }

   return 0;
}

Answer 1

Using pointer arithmetic, you can advance the start position of the printing, while specifying a length to printf() can be helpful, if you don't want to modify the string (in this case, we shorten the length by two, while advancing the pointer one position:

#include <stdio.h>
#include <string.h>

int main(int argc, char **argv)
{
    /* for each command line parameter passed to the program */
    for (int i = 1; i < argc; i++) {

        /* use a copy of the argv[i] pointer */
        char *s = argv[i];

        /* ... and print */
        for (int l = strlen(s); l > 0; l -= 2) {
            printf("%.*s\n", l, s++);
        }
    }
}

In the case you want a minimum code:

#include <stdio.h>
#include <string.h>

int main()
{
    const char *s = "Programming";
    for (int l = strlen(s); l > 0; l -= 2)
        printf("%.*s\n", l, s++);
}

or a pattern_print routine:

void print_pattern(const char *s)
{
    for (int l = strlen(s); l > 0; l -= 2)
        printf("%.*s\n", l, s++);
}