I want to loop over this list one item at a time, I want to have 0th element as constant and for every 0th element I want to have 1st,2nd,..... till last element and then repeat the process I.e for 1st element I want to have 2nd,3rd,4th.... last element and so on. I have tried for loop and while loop, but due to index error in the first cycle it is not going to the second cycle. Kindly guide. Thankyou in advance.
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type here
ls = ['aa','bb','cc','dd','ee','ff','gg','hh']
for i in range(len(ls)):
print("this is first loop", i)
j=i
while j <= len(ls):
print("this is second loop", j+1)
print("this is second loop", ls[j+1])
j+=1
this is first loop 0
this is second loop 1
this is second loop bb
this is second loop 2
this is second loop cc
this is second loop 3
this is second loop dd
this is second loop 4
this is second loop ee
this is second loop 5
this is second loop ff
this is second loop 6
this is second loop gg
this is second loop 7
this is second loop hh
this is second loop 8
Traceback (most recent call last):
print("this is second loop", ls[j+1])
IndexError: list index out of range
You can use a second for-loop like this:
ls = ['aa','bb','cc','dd','ee','ff','gg','hh']
for i in range(len(ls)):
print("this is first loop", i)
for j in range(i + 1, len(ls)):
print("this is second loop", j)
print("this is second loop", ls[j])