How to divide an odd number to get x integers?

Question

If I want to divide an odd number(for example 7) with 2 to 7, and I want a list of some integers. if I divine 7 with 4, I should get {1, 2, 2, 2}, or if I divine 5 with 3, I want to get {1, 2, 2}.

How can I do this?

        static List<int> OddNumDiv(int oddnum, int divnum)
        {
            List<int> result = new List<int>();

            result.Add(oddnum / divnum);
            int sum = 0;

            for (int i = 0; i < divnum - 2; i++)
            {
                sum += (int)Math.Round((double)oddnum / divnum, MidpointRounding.AwayFromZero);
                result.Add((int)Math.Round((double)oddnum / divnum, MidpointRounding.AwayFromZero));
            }
            result.Add(oddnum - sum);

            return result;
        }

        static void Main(string[] args)
        {
            List<int> _7d4 = OddNumDiv(7, 4);
        }

This returs with {1, 2, 2, 3} and not what I need {1, 2, 2, 2}

Answer 1

The very same idea as in samidinani answer (modulo arithmetic), but Linq implementation:

using System.Linq;

...

private static List<int> OddNumDiv(int oddnum, int divnum) => Enumerable
  .Range(0, divnum)
  .Select(i => oddnum / divnum + (i < divnum - oddnum % divnum ? 0 : 1))
  .ToList();

Fiddle