regexazureazure-data-factory
Regular expression in ADF
How to split the string based on white spaces in DataFlow expression builder in ADF pipeline. A string can have 1 or more white spaces.
Eg:
I used split(name,’ ‘) : Thiswill split the word based on single space.Some times it can have more than 1 space. How to handle that?
Joe Smith(1 white space)
Joel Smith(2 white space)
Joplin Smith(3 white space)
Solution
This is my sample data with spaces.
column
Steve Smith C S K
Rakesh Govindula Laddu
Chinna R C B
Use the below expression to get the words array without empty strings.
filter(split(column,' '),#item!='')
As there is no join function in dataflow expressions, to get the string of words with one space, use below expression from this SO Answer by @Jarred Jobe.
dropLeft(toString(reduce(filter(split(column,' '),#item!=''), '', #acc + ' ' + #item, #result)), 0)
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