SQL: trying to choose one options as an default when it has duplicated (oracle)

Question

I have some problem in SQL

My data is like this

Company	Report date	source
01	20071231	01
01	20081231	01
01	20081231	02
02	20071231	02
02	20081231	02
03	20071231	01
03	20071231	02

I want to choose '01' like an default in source column. But if not, then I want to choose source '02'

The result what I want is like this

Company	Report date	source
01	20071231	01
01	20081231	01
02	20071231	02
02	20081231	02
03	20071231	01

Thanks

select company
     , report date
     , source
from   (
        select *,
         count(*) over
           (partition by company, report date, source) as b
from the table
where b > 1

I cannot figure it out this result is true or not

Answer 1

Perhaps sorting rows per (company and date) by (source), so that 01 (if it exists) comes before 02 or any other value, and then extract rows that ranked as the highest?

Sample data:

SQL> with test (company, report_date, source) as
  2    (select '01', 20071231, '01' from dual union all
  3     select '01', 20081231, '01' from dual union all
  4     select '01', 20081231, '02' from dual union all
  5     select '02', 20071231, '02' from dual union all
  6     select '02', 20081231, '02' from dual union all
  7     select '03', 20071231, '01' from dual union all
  8     select '03', 20071231, '02' from dual
  9    ),

Query begins here:

 10  temp as
 11    (select company, report_date, source,
 12       row_number() over (partition by company, report_date order by source) rn
 13     from test
 14    )
 15  select company, report_date, source
 16  from temp
 17  where rn = 1;

COMPANY    REPORT_DATE SOURCE
---------- ----------- ----------
01            20071231 01
01            20081231 01
02            20071231 02
02            20081231 02
03            20071231 01

SQL>