I have this sample XML below:
<VqlQueryRestResult>
<data>
<row>
<Field3>BBB</Field3>
</row>
<row>
<Field3>CCC</Field3>
</row>
<row>
<Field3>AAA</Field3>
</row>
</data>
Tried the following Code but :
Node root = new XmlParser().parse(xml);
def orderNode = root.VqlQueryRestResult;
orderNode[0].children().sort(true) {it.item.Field3.text()}
I need to reorder it as below:
<VqlQueryRestResult>
<data>
<row>
<Field3>AAA</Field3>
</row>
<row>
<Field3>BBB</Field3>
</row>
<row>
<Field3>CCC</Field3>
</row>
</data>
</VqlQueryRestResult>
I would like to now sort this XML so that it goes to the correct position, please help
It worked with the code below:
def root = new XmlParser().parseText(msg);
root.data.each { it.children().sort { it.Field3.text() } }