I am trying to run an example script in C++ using GSL functions. I am using Visual Studio Code to compile and execute the program. The example code is below (I saved it under the file name gsl_bessel_example.cpp) and I got it directly from the GSL 2.7 Scientific Library documentation here.
#include <stdio.h>
#include <gsl\gsl_sf_bessel.h>
int
main (void)
{
double x = 5.0;
double y = gsl_sf_bessel_J0 (x);
//double y = 10.0;
printf ("J0(%g) = %.18e\n", x, y);
return 0;
}
I expect the program to output the following to the terminal after I have compiled and executed the program:
J0(5) = -1.775967713143382642e-01
When I compile the program, I use the following in the command line:
g++ -Wall gsl_bessel_example.cpp -IC:\msys64\mingw\include -LC:\msys64\mingw\lib -lgsl -lgslcblas
and execute it with:
.\a.exe
There are no errors or warnings given when I compile the file -- it compiles fine. However, I do not get any output when I execute it. If I comment out the line:
double y = gsl_sf_bessel_J0 (x);
and use:
double y = 10;
instead then recompile and execute, I receive an output I expect (see attached images for the results). Does anyone know why the file will not execute as expected when I use the GSL function? I have tried this for other examples provided in the GSL documentation but have similar results for all (no output).
This answer might be a bit late but I encountered the same problem and thought I'd share my solution.
Problem: the compiled binary cannot find the linked libgsl.dll and libgslcblas.dll libraries
Solution:
<gsl-path>\gsl\bin path to the PATH environment variableHere are the steps I took to find what the issue was:
libgsl.dll and libgslblas.dll files found in <gsl-path>\ gsl\bin in the same directory of the .exe and it workedgsl\bin folder to PATH environment variableI hope it helps.