Regex function to extract selected rows

I have a text file like this

Some text and random stuff that I don't need

2 8 
2 9 T
4 9
1 10 
2 10 F
7 11 T

More random stuff

How should I construct a regex function to extract both the rows with just numbers and the rows with numbers and T or F? So far my idea for the code is this

with open(file, 'r') as log_file:
    # opening file
        file = log_file
        while True:
            line = file.readlines()
            
            # if line in regex function:

                data.append(line)
                # closing file
                break

How can I solve this?

Solution

With this approach, the re pattern will match only numbers or numbers that end with the letter T or F. You could also use a for loop instead of a while loop.

import re

matched_data = []
with open(file, 'r') as log_file:
    data = log_file.readlines()
    
    for line in data:
        line = line.strip()
        if re.match(r'^\d+ \d+( [TF])?$', line):
            matched_data.append(line)
    
print(matched_data)

if some of the lines starts with a letter eg; T 7 11 and you want to match those as well, you should substitute the above pattern with r'^[TF]|\d+ \d+( [TF])?$'
Test Code:

import re

data = """
2 8 
2 9 T
4 9
1 10 
2 10 F
7 11 T
5 B 37
Y 9 G
T 7 11
MG 99 Z
"""

data = data.splitlines()
matched_data = []
for line in data:
    line = line.strip()
    if re.match(r'^\d+ \d+( [TF])?$', line):
        matched_data.append(line)
        
print(matched_data)
# ['2 8', '2 9 T', '4 9', '1 10', '2 10 F', '7 11 T']