get maximum number stored in a list

Question

example #1

numbers = ['1086', '1123', '543', '1180', '1222', '1300', '888']
print(max(numbers))

result: 888, desired result: 1300

example #2

numbers = ['1086', '1123', '1180', '1222', '1300']
print(max(numbers))

result: 1300, desired result: 1300

goal

numbers = ['1086', '1123', '543', '1180', '1222', '1300', '888']
print(max(numbers))

result: 1300, desired result: 1300

all 3 digit and 4 digit combinations should be involved

first 10 results from google index, that offering "enumarate", "max()", "sort()", [-1], [0] also different variations of "for" etc.. got me to write this question. at most brain dead copy/paste.

---

numbers = ['888','999','543']
print(max(numbers))

output is the maximum value, if all of 3 items in a list are 3 digits long, but with 4 digits it acts like this.

what is this?

numbers = ['888','999','543','1000','999.9']
print(max(numbers))
if float(max(numbers)) < 1000:
    print("hello?")

max() function should be fixed.

Answer 1

You list contains string not integers, you make use of map() to convert the string to integers:

numbers = ['1086', '1123', '543', '1180', '1222', '1300', '888']
print(max(map(int, numbers)))
>>> 1300