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Run bash script as source without source command

Is there any way to mark a script to be "run as source" so you don't have to add the source or "." command to it every time? i.e., if I write a script called "sup", I'd like to call it as

sup Argument

rather than

source sup Argument

or 

. sup Argument

Basically, I'm trying to use cd within a script.

Solution

  • Bash forks and starts a subshell way before it or your kernel even considers what it's supposed to do in there. It's not something you can "undo". So no, it's impossible.

    Thankfully.

    Look into bash functions instead:

    sup() {
    ...
}

    Put that in your ~/.bashrc.