Opening a window on top of other windows

Question

How to open a window on top of other windows when calling a function?

import wx
def openFile(wildcard="*"):
    app = wx.App(None)
    style = wx.FD_OPEN | wx.FD_FILE_MUST_EXIST
    dialog = wx.FileDialog(None, 'Open', wildcard=wildcard, style=style)
    if dialog.ShowModal() == wx.ID_OK:
        path = dialog.GetPath()
    else:
        dialog.Destroy()
        path = 'No file'
        return f'<div class="notification error">{path}</div>'
    dialog.Destroy()
    return f'<div id="pathToFile" class="notification">{path}</div>'

Answer 1

The Accepted answer from @VZ is spot on for all normal usage but strictly speaking, your code can be tweaked to work, even if it serves no real purpose but you'll notice, despite passing wx.STAY_ON_TOP, it will not honour it.

Like so:

import wx
def openFile(wildcard="*"):
    app = wx.App(None)
    style = wx.FD_OPEN | wx.FD_FILE_MUST_EXIST | wx.STAY_ON_TOP
    dialog = wx.FileDialog(None, 'Open', wildcard=wildcard, style=style)
    if dialog.ShowModal() == wx.ID_OK:
        path = dialog.GetPath()
    else:
        path = 'No file'
    dialog.Destroy()
    return f'<div class="notification error">{path}</div>'

print(openFile())