Using bash I would generate a regexp to match any formatted date between two dates. (I will later use it in restricted prod so I would use only bash as far as possible)
Random dates of course even crossing years for example the regexp might match any date between
so all of the dates
Time range comes from two parameters given as input to the future bash script.
Finaly will use that regexp to both find & manage filenames and to grep some datas.
Filename form-pattern are random but always contain a YYY-MM-DD time format, whatever the filename is from dd_YYYY-MM-DD.xx to aaaa__bbbb_dd_YYYY-MM-DD.xxx_ccc_zzz.log or anything else .
I tried to manage that by separating each year/month/day like
fromDate="$1"
toDate="$2"
# break the dates into array so that we can easily access the day, month and year
#
fdy=$( sed 's/.*\([0-9]\{4\}\).*/\1/' <<< $fromDate )
fdm=$( sed 's/.*-\([0-9]\{2\}\)-.*/\1/' <<< $fromDate )
fdd=$( sed 's/.*-.*-\([0-9]\{2\}\).*/\1/' <<< $fromDate )
#
edy=$( sed 's/.*\([0-9]\{4\}\).*/\1/' <<< $toDate )
edm=$( sed 's/.*-\([0-9]\{2\}\)-.*/\1/' <<< $toDate )
edd=$( sed 's/.*-.*-\([0-9]\{2\}\).*/\1/' <<< $toDate )
then to loop over that with some sort of
#[...]
printf -v date "%d-%02d-%02d" "${from[2]}" "${from[1]}" "${from[0]}"
pattern="$pattern|$date"
((from[0]++))
# reset days and increment month if days exceed 31
if [[ "${from[0]}" -gt 31 ]]
then
from[0]=1
((from[1]++))
#[...]
but didn't find a way to work around and output a correct regexp matching any date inside the date range.
This is not a regex solution but may be helpful.
When the date format is yyyy-mm-dd you can compare dates lexicographically.
The string "2023-01-05" is greater than "2022-08-05" because the first character they don't have in common is greater in the first string.
In bash you can therefore just do the comparison [[ "$date" > "$from" ]] && [[ "$to" > "$date" ]] to see if a date in yyyy-mm-dd string format is within the range $to-$from