Creating a box in Java from user inputs, but how do I replace the interior of the box with a different input than its borders?

Question

I need to create a box using user inputs. My inputs are the dimensions (height x width), the "interior" (the character that the box is filled with), and the "border" (the character surrounding the interior). I'm almost done, I believe; I can assemble the box given the dimensions and border, but I'm struggling to figure out how to fill the inside.

I don't know how to use decision statements to determine which characters belong on which line. If the current line is the first line, I want to print only border characters, or if the current character on the line is the first character in that line, print a border character, but print the interior for the following characters (until the end char), etc.

My code:

// Below this comment: import the Scanner
import java.util.Scanner;
public class Box {
   public static void main(String[] args) {
      // Below this comment: declare and instantiate a Scanner
      Scanner scnr = new Scanner(System.in);

      // Below this comment: declare any other variables you may need
      int width;
      int height;
      char border;
      char interior;


      // Below this comment: collect the required inputs
      System.out.println("Enter width    : ");
      width = scnr.nextInt();
      System.out.println("Enter height   : ");
      height = scnr.nextInt();
      System.out.println("Enter border   : ");
      border = scnr.next().charAt(0);
      System.out.print("Enter interior : ");
      interior = scnr.next().charAt(0);


      // Below this comment: display the required results

      for (int j = 0; j < height; j++) {
         for (int i = 1; i < width; i++) {
            System.out.print(border);
         }
         System.out.print(border);
         System.out.println("");
      }
   }
}

As an arbitrary example, running my code with 7x5 dimensions and X and O characters gives me:

XXXXXXX
XXXXXXX
XXXXXXX
XXXXXXX

But my desired result would be:

XXXXXXX
XOOOOOX
XOOOOOX
XOOOOOX
XXXXXXX

Answer 1

Change:

for (int j = 0; j < height; j++) {
  for (int i = 1; i < width; i++) {
    System.out.print(border);
  }
  System.out.print(border);
  System.out.println("");
}

To:

for (int j = 0; j < height; j++) {
  for (int i = 1; i <= width; i++) {
    if (j==0 || j==(height-1)) {
      System.out.print(border);
    }
    else {
      if (i==1 || i==width) {
        System.out.print(border);
      }
      else {
        System.out.print(interior);
      }  
    }
  }
  System.out.println();
}

This could obviously be written in many different ways, some much more compact than this. I think this way is easy to understand, though...

For instance, here's a shorter version that works, but is harder to interpret:

for (int j = 0; j < height; j++) {
  for (int i = 1; i <= width; i++) {
    System.out.print(((j==0 || j==(height-1)) || (i==1 || i==width)) ? border : interior);
  }
  System.out.println();
}