I have an $I$-indexed array $V = (V_i)_{i \in I}$ of (column) vectors $V_i$, which I want to multiply pointwise (along $i \in I$) by a matrix $M$. So I'm looking for a "vectorized" operation, wherein the individual operation is a multiplication of a matrix with a vector; that is
$W = (M V_i)_{i \in I}$
Is there a numpy way to do this?
numpy.dot
unfortunately assumes that $V$ is a matrix, instead of an $I$-indexed family of vectors, which obviously fails.
So basically I want to "vectorize" the operation
W = [np.dot(M, V[i]) for i in range(N)]
Considering the 2D array V as a list (first index) of column vectors (second index).
If
shape(M) == (2, 2)
shape(V) == (N, 2)
Then
shape(W) == (N, 2)
Based on your iterative example, it seems it can be done with a dot product with some transposes to match the shapes. This is the same as (M@V.T).T
which is the transpose of M @ V.T.
# Step by step
((2,2) @ (5,2).T).T
-> ((2,2) @ (2,5)).T
-> (2,5).T
-> (5,2)
Code to prove this is as follows. Your iterative output results in a matrix W
which is exactly equal to the solutions
matrix.
M = np.random.random((2,2))
V = np.random.random((5,2))
# YOUR ITERATIVE SOLUTION (STACKED AS MATRIX)
W = np.stack([np.dot(M, V[i]) for i in range(5)])
print(W)
#array([[0.71663319, 0.84053871],
# [0.28626354, 0.36282745],
# [0.26865497, 0.55552295],
# [0.40165606, 0.10177711],
# [0.33950909, 0.54215385]])
# PROPOSED DOT PRODUCt
solution = (M@V.T).T #<---------------
print(solution)
#array([[0.71663319, 0.84053871],
# [0.28626354, 0.36282745],
# [0.26865497, 0.55552295],
# [0.40165606, 0.10177711],
# [0.33950909, 0.54215385]])
np.allclose(W, solution) #compare the 2 matrices
True
IIUC, your ar elooking for a pointwise multiplication of a matrix M
and vector V
(with broadcasting).
The matrix here is (3,3)
, while V
is an array with 4 column vectors, each of which you want to independently multiply with the matrix while obeying broadcasting rules.
# Broadcasting Rules
M -> 3, 3
V -> 4, 1, 3 #V.T[:,None,:]
----------------
R -> 4, 3, 3
----------------
Code for this -
M = np.array([[1,1,1],
[0,0,0],
[1,1,1]]) #3,3 matrix M
V = np.array([[1,2,3,4],
[1,2,3,4], #4,3 indexed vector
[1,2,3,4]]) #store 4 column vectors
R = M * V.T[:,None,:] #<--------------
R
array([[[1, 1, 1],
[0, 0, 0],
[1, 1, 1]],
[[2, 2, 2],
[0, 0, 0],
[2, 2, 2]],
[[3, 3, 3],
[0, 0, 0],
[3, 3, 3]],
[[4, 4, 4],
[0, 0, 0],
[4, 4, 4]]])
Post this if you have any aggregation, you can reduce the matrix with the required operations.
Example, Matrix M
* Column vector [1,1,1]
results in -
array([[[1, 1, 1],
[0, 0, 0],
[1, 1, 1]],
while, Matrix M
* Column vector [4,4,4]
results in -
array([[[4, 4, 4],
[0, 0, 0],
[4, 4, 4]],