//Username and Password
#include<stdio.h>
#include <string.h>
void
main ()
{
const char *arr[] =
{ "lonely_wolf69", "Alpha_male420", "jojo_rabbit77",
"secrethitleradmirer" };
char a, *pass = "steverogersrox", n;
int i, flag = 0;
printf ("Enter Username: ");
scanf ("%c", &a);
if (memchr (arr, a, sizeof (arr)))
{
for (i = 0; i < 3; i++)
{
printf (" \n Enter Password: ");
scanf ("%c", &n);
if (n == *pass)
{
printf ("\n Login Successfull");
break;
}
else
{
printf ("Wrong Password, Try Again.");
flag++;
}
}
}
else
printf ("User Not Found");
if (flag == 3)
printf ("\n You have been Blocked out of the system.");
}
Whatever I am entering, its Just Showing User Not Found. Note: I know.....very tedious....but looking to understand the concept first and clean up later, also any smarter Ideas are always encouraged.
After 3 Excruciating Days.....I Finally did it. Small But I'm really Proud
''''
#include<stdio.h>
#include<string.h>
void
main ()
{
int attempts = 3, i, n = 0;
char user[20], pass[20];
const char *user_list[] =
{ "lonely_wolf69", "Alpha_male420", "jojo_rabbit77",
"secrethitleradmirer", "johnlennonbutpoor"
};
printf ("Enter Your Username: ");
scanf ("%s", user);
//for all elements of the list check if name present
for (i = 0; i < sizeof (user_list) / sizeof (user_list[1]); i++) //size of finds the lenght of array
{
if (strcmp (user, user_list[i]) == 0)
{
n = 1;
}
}
if (n == 1)
{
while (attempts > 0)
{
printf ("\n Enter Password: ");
scanf ("%s", pass);
if (strcmp (pass, "love") == 0)
{
printf ("Login Successful");
break;
}
else
{
attempts--;
if (attempts == 0)
break;
printf ("\n Wrong Password! Try Again. %d attempt(s) left",
attempts);
}
}
}
if (n != 1)
printf ("User Not Found.");
if (attempts == 0)
printf ("You Have Been Blocked");
}
''''