how can I compare two lists in python and if I have matches ~> I want matches and next value from another list

Question

a = [’bww’, ’1’, ’23’, ’honda’, ’2’, ’55’, ’ford’, ’11’, ’88’, ’tesla’, ’15’, ’1’, ’kia’, ’2’, ’3’]

b = [’ford’, ’honda’]

should return all matches and next value from list a

Result -> [’ford’, ’11’, ’honda’, ’2’] or even better [’ford 11’, ’honda 2’]

I am new with python and asking help

Answer 1

Assuming all are in string type also assuming after every name in the list a there will be a number next to him.

Code:-

a = ['bww', '1', 'honda', '2', 'ford', '11', 'tesla', '15', 'nissan', '2']
b = ['ford', 'honda']

res=[]
for check in b:
    for index in range(len(a)-1):
        if check==a[index]:
            res.append(check+" "+a[index+1])
print(res)

Output:-

['ford 11', 'honda 2']

List comprehension

Code:-

a = ['bww', '1', 'honda', '2', 'ford', '11', 'tesla', '15', 'nissan', '2']
b = ['ford', 'honda']

res=[check+" "+a[index+1] for check in b  for index in range(len(a)-1) if check==a[index]]

print(res) #Same output