var error = new Error(message); Why am I getting this message in the terminal?

Question

Everything works effectively until I add the const amountOut to the file.

Code with Error & location of function that breaks code

Answer 1

You are passing 2 parameters into a function that is expecting 3. The second parameter is one value because you have it as an array in brackets - [AddressFrom, AddressTo].

You will need to either modify how you are passing in the parameters to the getAmountsOut function or modify the getAmountsOut function to accept 2 parameters, with one being an array.